225k views
1 vote
Solve the equation. Identify any extraneous solutions.

h = sqrt 3h

-3 is a solution of the original equation. 0 is an extraneous solution.

0 and 3 are solutions of the original equation.

3 is a solution of the original equation. 0 is an extraneous solution.

0 is a solution of the original equation. 3 is an extraneous solution.

User Lekso
by
8.1k points

2 Answers

2 votes

Answer:0 and 3 are solutions of the original equation.

Explanation:

User Lory
by
7.7k points
3 votes

Answer:

It's the second option:

0 and 3 are both solutions.

Explanation:

h = √(3h) Square both sides:

h^2 = 3h

h^2 - 3h = 0

h(h - 3) = 0

h = 0, 3.

If we plug h = 0 into the original equation:

0 = √(3*0) = 0 so this is a root.

x = 3:

3 = √(3*3) = 3 so this is also a root.

User Vdudouyt
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories