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4x^2 -20x +25≥0​

1 Answer

3 votes

Answer:

x ≥
(5)/(2)

Explanation:

Given equation:

4x² -20x + 25≥0​

To solve for x, we simply factorize the equation;

We should find two numbers whose sum = -20 and product is 100

These two numbers are -10 and -10

So;

4x² - 10x - 10x + 25 ≥ 0​

factorize;

2x(2x - 5) - 5(2x - 5) ≥ 0​

(2x - 5) (2x - 5) ≥ 0​

So;

2x - 5 ≥ 0​

2x ≥ 5

x ≥
(5)/(2)

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