Answer:
Option C:Vertex = (–2,–25), y-intercept = (0,–21), x-intercepts = (–7,0) and (3,0), axis of symmetry is x = –2
Explanation:
We are given the function;
f(x) = (x - 3)(x + 7)
The axis of symmetry in a quadratic equation is given by the formula;
x = -b/2a
Expanding the function given, we have;
f(x) = x² + 4x - 21
a = 1
b = 4
c = - 21
Thus;
Axis of symmetry is:
x = -(4)/(2 × 1)
x = -2
Now, y-intercept is when x = 0
Thus;
f(0) = (0 - 3)(0 + 7)
f(0) = - 3 × 7 = - 21
y - intercept is (0, - 21)
x-intercept is when f(x) = 0
Thus;
(x - 3)(x + 7) = 0
Thus;
x - 3 = 0 or x + 7 = 0
x = 3 or x = - 7
x - intercept is (-7, 0) and (3,0)
The y-coordinate of vertex will be at the line of axis of symmetry.
Thus, we will put x = -2 into the function to get;
y = (-2 - 3)(-2 + 7)
y = -5 × 5 = - 25
Vertex is at (-2, -25)
Correct Answer is option C