Question

The length of a rectangle is twice the width. the area is 512 yd2 find the length and the width

Answer 1

`\sf\huge \green{\underbrace{\red{Answer}}}:`

length is 32yd and width is 16yd

Explanation:

Let the width of rectangle(b) be x

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The length of rectangle(l) = 2x

(as it is twice the width)

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Area = 512yd² (given)

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`\sf Area = l ength * width \\ \\ \\ \sf \implies 512 = 2x * x \\ \\ \\ \sf \implies 512 = 2 {x}^(2) \\ \\ \\ \sf \implies (512)/(2) = {x}^(2) \\ \\ \\ \sf \implies 256 = {x}^(2) \\ \\ \\ \sf \implies √(256) = x \\ \\ \\ \red{\boxed{ \implies 16 = x}}`

Width = 16 yd

length = 2×16 = 32 yd