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20 votes
Simplify:

1. Cos(90°-x).sin(-x)/cos² (180°+x)
2. tan² (360° + 0)/cos(90° +0).sin(180° - 0)

NB. The 0 is meant for theta​

User Jannej
by
3.5k points

1 Answer

8 votes

1.

cos(90-x) = sin(x)

sin(-x) = -sin(x)

cos²(180+x) = (-cos²x) = cos²(x)

Then

cos(90-x) .sin(-x)/cos²(180+x) = sin(x).(-sin(x))/cos²(x)

= -sin²(x))/cos²(x)

= −tan²(x)

2.

tan² (360° + θ)/cos(90° + θ).sin(180° - θ)

tan² (360° + θ) = tan² (θ)

cos(90° +x) = - sin(θ)

sin(180° - θ) = sin(θ)

tan² (360° + θ)/cos(90° +θ).sin(180° - θ) = tan² (θ)/- sin(θ) sin(θ)

= -tan²(θ)/sin²(θ)

= -1/cos²(θ)

= - (cos²θ + sin²θ)/cos²θ

= -1 - tan²θ

User Erwin Van Ekeren
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3.7k points