Question

A 30.0-kgkg box is being pulled across a carpeted floor by a horizontal force of 230 NN , against a friction force of 210 NN . What is the acceleration of the box?

Answer 1

The acceleration of the box is 0.67 m/s²

Step-by-step explanation:

Given that,

Mass of box = 30.0 kg

Horizontal force = 230 N

Friction force = 210 N

We need to calculate the acceleration of the box

Using balance equation

`F-f_(k)=ma`

`a=(F-f_(k))/(m)`

Where, F = horizontal force

`f_(k)` =frictional force

m= mass of box

a = acceleration

Put the value into the formula

`a=(230-210)/(30)`

`a=0.67\ m/s^2`

Hence, The acceleration of the box is 0.67 m/s²