Question

If the neutron microscopic absorption cross section of boron at 0.0253 eV is 3847 barns, what would it be at 0.1 eV? [ Ans. 1935 b ]

Answer 1

The correct answer will be "1935 barns".

Step-by-step explanation:

The given values are:

`E_(1)` = 0.0253 eV

`E_(2)` = 0.1 eV

`\sigma_(2)` = 3847 barns

Now,

⇒
`(\sigma_(1))/(\sigma_(2)) = (E_(1))/(E_(2))`

then,

⇒
`\sigma_(1)=\sigma_(2)\sqrt{(E_(1))/(E_(2))`

On substituting the given values, we get

⇒
`=3847* \sqrt{(0.0253)/(0.1) }`

⇒
`=1935 \ barns`