Answer:
A) M'(w) = w^16 * 4^w [ 51 + 3w In4 ]
B) h'(t) = [ cos (t) - sin (t) ] t^4 + [ sin(t) + cos (t) ] 4t^3
C) f'(1) = e' [sin(1) + cos(1) ]
D) g'(a) = 0 - 1/2
L(x) = - 1/2 ( x + 1 )
Explanation:
Attached below is the detailed solution of the problem
A) m(w) = 3w^17 * 4^w
M'(w) = w^16 * 4^w [ 51 + 3w In4 ]
B) h(t) = [sin(t) + cos(t) ] t^4
h'(t) = [ cos (t) - sin (t) ] t^4 + [ sin(t) + cos (t) ] 4t^3
C) f(x) = e^x sin (x). at a = -1
f'(1) = e' [sin(1) + cos(1) ]
D) g (x) = ( x^2 + x ) 2^x .
g'(a) = 0 - 1/2
L(x) = - 1/2 ( x + 1 )