151k views
4 votes
What would you use to solve for a?

a
43
11
A
A. sine
B. cosine
C. tangent D. Pythagorean Theorem

What would you use to solve for a? a 43 11 A A. sine B. cosine C. tangent D. Pythagorean-example-1
User Kundan Roy
by
7.1k points

2 Answers

3 votes

Answer:

Cosine

Explanation:

There are 2 angles present and 1 length present, therefore you would use cosine.

User ColemanTO
by
6.3k points
4 votes

To solve for
a tangent will be used because, tan theta equals to opposite side length divide by adjacent side length. Therefore, option C is correct

To solve for side
\( a \) in the right-angled triangle where
\( a \) is the side opposite the
\( 43^\circ \) angle, and the adjacent side is 11 units, we use the tangent function. The tangent of an angle in a right triangle is the ratio of the length of the opposite side to the length of the adjacent side.

The formula for tangent is:


\[\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}\]

Substituting the given values into the formula:


\[\tan(43^\circ) = (a)/(11)\]

To find
a, we rearrange the formula to solve for the opposite side:


\[a = 11 * \tan(43^\circ)\]

Using a calculator, we find that
\( \tan(43^\circ) \) is approximately
\( 0.93251508613704 \). Multiplying this by the length of the adjacent side (11 units), we get:


\[a \approx 11 * 0.93251508613704 \approx 10.26 \text{ units}\]

Therefore, the length of side
a opposite the
\( 43^\circ \) angle is approximately
\( 10.26 \) units.

User Ruthger Righart
by
6.3k points