Question

How much heat, in kilojoules, must be added to a 580 g aluminum pan to raise its temperature from 25∘C to 150∘C?

---The specific heat capacity for aluminum is 0.897 J/g∘C.
---Round the answer to two significant figures.

Answer 1

Q = 65 kJ

Step-by-step explanation:

Given that,

Mass, m = 580 g

Initial temperature,
`T_i=25^(\circ) C`

Final temperature,
`T_f=150^(\circ) C`

The specific heat capacity for aluminum is 0.897 J/g°C

We need to find the heat added to the aluminium pan so that its heat raised to a temperature from 25°C to 150°C. It is given by :

`Q=mc\Delta T\\\\Q=580\ g* 0.897\ J/g^(\circ) C* (150-25)^(\circ) C\\\\Q=65032.5\ J`

or

Q = 65.03 kJ

or

Q = 65 kJ

Hence, the heat added to the pan is 65 kJ.