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Solve.
x^2 + 4 = 0.

Solve. x^2 + 4 = 0.-example-1
User Kares
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2 Answers

3 votes

Answer:

No real solutions

Explanation:

User Safhac
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You use the quadratic formula.

x = −b ± √(b^2 − 4ac)/2a where y = ax^2 + bx + c

b is 0, a is 1, and c is 4.

-0 ± √(0^2 − 4 x 1 x 4)/ 2(1)

±√(-16)/2

Split √(-16) into √(16) and √(-1).

Now, i = √-1

So you get ±√(-16) = ±4i.

The original equation was ±√(-16)/2.

±4i / 2 = ±2i

The answer is x = ±2i

(Note: ± means positive or negative)

User Jarred Olson
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