Question

How many fluorine atoms are present in 6.30 g of C2F4

Answer 1

Fluorine atoms = 1.517 x 10²³

Further explanation

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

`\large{\boxed{\boxed{\bold{mol=(mass)/(molar\:mass)}}}`

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

• Mass of F

`\tt mass~F=(4.Ar~F)/(MW~C_2F_4)* mass~C_2F_4\\\\mass~F=(4.19)/(100)* 6.3=4.788~gr`

• mol of F

`\tt =(4.788)/(19)=0.252`

• number of Fluorine atoms

`\tt 0.252* 6.02* 10^(23)=1.517* 10^(23)`