Question

Which of the equations shown will have infinitely many solutions? Select the TWO that apply. A 3x−1=3x+13 x minus 1 is equal to 3 x plus 1 B 2x−1=1−2x2 x minus 1 is equal to 1 minus 2 x C 3(x−1)=3x−33 times open paren x minus 1 close paren is equal to 3 x minus 3 D 2x+2=2(x+1)2 x plus 2 is equal to 2 times open paren x plus 1 close paren E 3(x−2)=2(x−3)

Answer 1

3x-1 = 3x+1

3(x-1) = 3x+3

Answer 2

Explanation:

Am equation with infinite number of solution means that the equation has uncountable solutions.

Let's analyse each options

For the expression 3x-1 = 3x+1

Collect like terms

3x-3x = 1+1

0x = 2

Divide both sides by 0

x = 2/0

x = infinity

This shows that the expression 3x-1 = 3x+1 has infinite number of solution

Also considering the third expression

3(x-1) = 3x+3

Open the parenthesis

3x-3 = 3x+3

Collect like terms

3x-3x = 3+3

0x = 6

x = 6/0.

x = infinity

Thus also shows that expression 3(x-1) = 3x+3 has infinite number of solution.