Given:
Graph of positions of Bear A and Bear B.
To find:
The average speed of Bear B in m/min.
Solution:
From the graph it is clear that initial point of graph of Bear B is (0,100) and the end point is (60,2800).
The average speed of Bear B is
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6g6za4c720e5154tr4m4qzakkci1x13a8r.png)
![m=(2800-100)/(60-0)](https://img.qammunity.org/2021/formulas/mathematics/college/be1e7kg67ob9wo3b0h12e08crzeckhfxbt.png)
![m=(2700)/(60)](https://img.qammunity.org/2021/formulas/mathematics/college/5g5mlx51gnwznaokgmmtzn2yjk9ud5qir6.png)
![m=45](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lkdcswkub8iivwppc1a0aaywqni8zemrpl.png)
Therefore, the average speed of Bear B is 45 m/min.