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18 votes
What is the period, in seconds, of a simple pendulum of length 5 meters? Use

the gravitational constant g = 9.8 m/s2 and round your answer to two decimal
places.

User VarunVyas
by
4.4k points

1 Answer

10 votes


T=2\pi \sqrt{((l)/(g) )} \\T=2\pi \sqrt{(5m)/((9.8m/s^(2)) ) } \\


T
4,49s

User John Kocktoasten
by
5.1k points