Answer:
One solution, as there is only one intersection between these two lines.
x = 2, and y = 1 (point of interesection (2, 1) )
y = 2x-3
y = -x + 3
first step is to substitute the y of one equation into the other and solve for x.
- x + 3 = 2x - 3
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+x. +x
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3 = 3x-3
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+3 +3
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6 = 3x
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÷3 ÷3
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2 = x
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x = 2
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We can verify this value is true by substituting it back into the equations and as a result also solving for the working y value.
x = 2 -> y = 2(x) - 3
2(2) - 3 = 4 - 3 = 1
y = 1
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x = 2 -> y = -(x) + 3
-(2) + 3 = -2 + 3 = 1
y = 1