Question

The temperature of aluminum increases from 30.0 to 38.0 °C and absorbed 900.J. Calculate the mass of aluminum used if the specific heat is 0.902 J/gK.

please help!!!!

Answer 1

The mass of aluminum is 124.72 g

Step-by-step explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of energy that causes a change in the temperature of a substance. In other words, sensible heat is that heat that causes the temperature of an object to vary without affecting its molecular structure and therefore its physical state. Its mathematical expression is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

• Q= 900 J
• c= 0.902
  `(J)/(g*K)`
• m= ?

• ΔT= Tfinal - Tinitial= 38 °C - 30°C= 8°C as it is a temperature difference, it is indistinct if the temperature is expressed in ° C or ° K because the difference will be the same. So: ΔT= 8°C= 8 °K

Replacing:

900 J= 0.902
`(J)/(g*K)` *m* 8 °K

900 J= 7.216
`(J)/(g)` *m

`(900 J)/(7.216(J)/(g) ) =m`

124.72 g=m

The mass of aluminum is 124.72 g