78.8k views
0 votes
The population of a certain town was 50,000.In a year,male population

was increased by 5% and female population was increased by 3%. Now
the population beame 52020. Then what was the number of males and
females in the previous year?
olution:- Let the number of males in previous year be x,number of females​

User Tony Cho
by
7.7k points

1 Answer

0 votes

Answer: Male population = 26,000

Female population = 24,000

Step-by-step explanation: Male population = X

Female population = Y

x+y=50,000

y=50,000-x-(1st equation)

Again (x+x X 5%) + (y+y X 3%) = 52,020

-> x+5x/100 + y+3y/100 = 52020

-> 100x+5x+100y+3y =52020

________________

100

-> 105x+103y = 52020-( 2nd Equation)

Putting Eq 1 into 2 ,

105x+103 ( 50,000-x)= 52,020

-> 105x + 5,150,000-103x = 52,020

->2x = 52,020-5,150,000

->2x = 52,000

x = 26,000 (Male population)

y = 50,000-26,000

= 24,000 (Female population)

User Erik Peterson
by
8.7k points

Related questions

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories