Answer:
The time it will take to raise the temperature of 850 kg of steel from 15°C to 45°C is approximately 0.11064 hours
Step-by-step explanation:
The given parameters are;
The mass of the steel = 850 kg
The temperature of the water of the ocean = 45°C
The temperature of the steel = 15°C
The heat capacity for steel, c = 0.46 kJ/(kg·K)
Therefore, the heat, ΔQ required to raise the temperature of 850 kg of steel from 15°C to 45°C is given as follows;
ΔQ = The mass of steel × The heat capacity for steel × The rise in temperature
ΔQ = 850 kg ×0.46 kJ/(kg·K) × (45 - 15)°C = 11730 kJ = 11730 × 10³J
The rate of heat transfer = 29.45 × 10³ W = 29.45 × 10³ J/S
Therefore, the time, t, it will take to absorb 11730 kJ is given as follows;
t = (11730 × 10³J)/(29.45 × 10³ J/S) ≈ 398.3 seconds
t ≈ 398.3 seconds = 398.3 seconds ×1/60 minutes/second × 1/60 hour/minute
t ≈ 0.11064 hours
The time it will take to raise the temperature of 850 kg of steel from 15°C to 45°C ≈ 0.11064 hours.