Answer:
5.45 m/s
Step-by-step explanation:
Given:
Δx = 2.08 m
v₀ₓ = v₀ cos 44°
aₓ = 0 m/s²
Δx = v₀ₓ t + ½ aₓ t²
2.08 m = (v₀ cos 44°) t + ½ (0 m/s²) t²
2.89 = v₀ t
Given:
Δy = 0.63 m
v₀ᵧ = v₀ sin 44°
aᵧ = -9.81 m/s²
Δy = v₀ᵧ t + ½ aᵧ t²
0.63 m = (v₀ sin 44°) t + ½ (-9.81 m/s²) t²
0.63 = 0.695 v₀ t − 4.905 t²
0.63 = 0.695 (2.89) − 4.905 t²
t = 0.530
v₀ = 5.45 m/s