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(40x^3y^6)/(-8x^2y) PLEASE HELP!

User Ado Ren
by
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2 Answers

3 votes

Answer:


\huge\boxed{(40x^3y^6)/(-8x^2y)=-5xy^5}

Explanation:


(40x^3y^6)/(-8x^2y)=(40)/(-8)\cdot(x^3)/(x^2)\cdot(y^6)/(y)\\\\\text{use}\ (a^n)/(a^m)=a^(n-m)\\\\=-5x^(3-2)y^(6-1)=-5x^1y^5=-5xy^5

User EvanGWatkins
by
7.9k points
6 votes

Answer:

here's my answer...........

(40x^3y^6)/(-8x^2y) PLEASE HELP!-example-1
User Steve Ruben
by
7.3k points

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