(40x^3y^6)/(-8x^2y) PLEASE HELP!

asked Jul 15, 2021 119k views

2 votes

PLEASE HELP!

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3 votes

Answer:

$\huge\boxed{(40x^3y^6)/(-8x^2y)=-5xy^5}$

Explanation:

$(40x^3y^6)/(-8x^2y)=(40)/(-8)\cdot(x^3)/(x^2)\cdot(y^6)/(y)\\\\\text{use}\ (a^n)/(a^m)=a^(n-m)\\\\=-5x^(3-2)y^(6-1)=-5x^1y^5=-5xy^5$

EvanGWatkins answered Jul 18, 2021

5.7k points

6 votes

Answer:

here's my answer...........

Steve Ruben answered Jul 20, 2021

5.6k points

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