We can use the subtraction property of logs to expand the right side of the equation:
log(1/H*) = log(1) - log(H*)
No matter what base we’re using, log(1) = 0, so this simplifies to -log(H*). We’re also given a pH value of 3.6, so we can substitute this value into the original equation along with -log(H*) to get
3.6 = -log(H*)
Multiplying by -1 on both sides:
-3.6 = log(H*)
And rewriting in exponential form:
H* = 10^(-3.6) = 0.0003 (rounded to the nearest ten thousandth)