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The lab technician you recently hired tells you the following: Boss, an undisturbed sample of saturated clayey soil was brought to me from the Mission Valley site. I measured the mass of the sample to be 600 grams. I then measured the mass of the sample after placing it in the oven for 24 hrs. I found this mass to be 200 grams. Can you help me determine the water content?" Determine the water content.

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Answer:

The water of the saturated clayed soil is 66.67 %.

Step-by-step explanation:

Given;

mass of saturated clayed soil,
M_s = 600 g

mass of dry soil sample,
M_d = 200 g

mass of water content,
M_w =
M_s -
M_d = 600 g - 200 g = 400 g

The water content is determined as;


M_w(\%) = (M_s - M_d)/(M_s) *100\%\\\\M_w(\%) = (600-200)/(600) *100 \% \\\\M_w(\%) = 66.67 \%

Therefore, the water of the saturated clayed soil is 66.67 %.

User Rorymadden
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