Answer:
The pressure if the volume becomes 6.8L would be 4.19atm
Step-by-step explanation:
Boyle's law:
P1 V1= P2 V2
P1 = 0. 6 atm
P2 = ?
V1 = 47. 5 L
V2 = 6. 8 L
P2 = 0.6 × 47.5 ÷ 6.8
P2 = 4.19 atm
The pressure if the volume becomes 6.8L is 4.19atm
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