144k views
1 vote
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(negative 3, 6), B(2, 9), and C(1, 1)

User Stas BZ
by
5.2k points

1 Answer

5 votes

Note: Consider we need to find the vertices of the triangle A'B'C'

Given:

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).

To find:

The vertices of the triangle A'B'C'.

Solution:

If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then


(x,y)\to (y,-x)

Using this rule, we get


A(-3,6)\to A'(6,3)


B(2,9)\to B'(9,-2)


C(1,1)\to C'(1,-1)

Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).

User Brennan Hoeting
by
5.9k points