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Find the perimeter & area of the rectangle

Find the perimeter & area of the rectangle-example-1

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Answer:

Perimeter =
34√(2) feet

Area = 60 feet²

Explanation:

Let us revise the rules of perimeter and area of a rectangle

  • Perimeter = 2(Length + width)
  • Area = Length × Width

→ From the given figure

∵ The length =
√(8) feet

∵ The width = 5
√(18) feet

→ Simplify the roots


√(8)=√((2)(2)(2))


√(8)=2√(2)

∴ The length =
2√(2) feet


5√(18)=5√((3)(3)(2))


5√(18)=5(3)√(2)=15√(2)

∴ The width =
15√(2) feet

→ Perimeter = 2(Length + width)

∵ Perimeter =
2[2√(2)+15√(2)]

∴ Perimeter =
2[17√(2)]

∴ Perimeter =
34√(2) feet

→ Area = Length × Width

∵ Area =
2√(2) ×
15√(2)

∴ Area =
(2)(15)(√(2))(√(2))=(30)(2)=60

∴ Area = 60 feet²

User Gappy
by
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