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The area of a rectangle is 24 cm² and the perimeter is 22 cm .What is the lenth and width of this rectangle?

1 Answer

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Explanation:

length × width = 24

2×length + 2×width = 22

length + width = 11

length = 11 - width

this we use in the first equation again :

(11 - width) × width = 24

11×width - width² = 24

width² - 11×width + 24 = 0

the general solution to an quadratic equation :

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = width

a = 1

b = -11

c = 24

and so we get

width = (11 ± sqrt((-11)² - 4×1×24))/2×1) =

= (11 ± sqrt(11² - 96))/2 = (11 ± sqrt(121-96))/2 =

= (11 ± sqrt(25))/2 = (11 ± 5)/2

width1 = (11 + 5)/2 = 16/2 = 8 cm

width2 = (11 - 5)/2 = 6/2 = 3 cm

and teenaged to this is then

length1 = 11 - width1 = 11 - 8 = 3 cm

length2 = 11 - width2 = 11 - 3 = 8 cm

so, it is clear. one dimension has to be 8 cm, and the other one 3 cm. it does not matter which is which.

User Satyam Gondhale
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