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Identify the translation rule on a coordinate plane that verifies that square A(-4, 3), B(-4, 8), C(-9, 3), D(-9, 8) and square A'(-3, 2), B'(-3, 7), C'(-8, 2), D'(-8, 7) are congruent.
A) (x, y) → (x - 1, y + 1)
B) (x, y) → (x - 1, y - 1)
C) (x, y) → (x + 1, y - 1)
D) The squares are not congruent

2 Answers

4 votes

Answer:

The translation rule is:

Option: C

(x, y) → (x + 1, y + 1)

Explanation:

We are given the vertices of a square A(-4,3), B(-4,8), C(-9,3), D(-9,8) and square A'(-3,4), B'(-3,9), C'(-8,4), D'(-8,9) .

We have to find the translation rule on a coordinate plane that verifies that square ABCD is congruent to square A'B'C'D'.

Since, the two squares o be congruent every vertex must be translated by the same rule.

So, the rule is:

(x, y) → (x + 1, y + 1)

since,

A(-4,3) → A'(-4+1,3+1)=A'(-3,4)

B(-4,8) →B'(-4+1,8+1)=(-3,9)

C(-9,3) → C'(-9+1,3+1)=(-8,4)

and D(-9,8) → D'(-9+1,8+1)=(-8,9)

Hence, the translation rule is:

Option: C

(x, y) → (x + 1, y + 1)

Explanation:

User Edwin Lunando
by
8.2k points
4 votes

Answer:

C) (x+1, y-1)

Explanation:

Because if you look at the corresponding points 1 is added to the x-value of the original point and 1 is subtracted from the y-value of the original point

User Andreas Kahler
by
8.9k points

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