Answer:
18 years
Explanation:
The formula for computing accrued amount A for a principal of P at an interest rate of r(in decimal) compounded n times in a year for t years is given by
![A = P(1 + (r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/college/2es43wifkrrwvix75szgtnpoqmgr2j2yjp.png)
Note that r is percentage converted to decimal. So 3% = 3/100 = 0.03
We can rearrange the above equation to:
![(A)/(P) = (1 + (r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/college/xr5j7cyh6uxvcxj4dj3unes7h6gpaqpoxr.png)
Taking logs on both sides
![log((A)/(P)) = log(1 + (r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/college/gtc37sgwyyki6vsj5fm0ply29gtdruiazi.png)
This gives
![log((A)/(P)) =nt * log(1 + (r)/(n))\\So,\\nt = (log((A)/(P)))/( log(1 + (r)/(n)))](https://img.qammunity.org/2023/formulas/mathematics/college/o5t2jowqftb9jdbj8bxk2hgz54ob2gzm6o.png)
In this particular problem, n = 4, , A= 9600, P = 5600, r =0.03, so r/n = 0.03/4 = 0.0075
1 + r/n = 1+0.0075 = 1.0075
4t = log(9600/5600)/log(1.0075) = log(1.714) / log(1.0075) = 0.234 /0.00325 = 72
t = 72/4 = 18 years