Question

Help!! plz!!

Write an equation that is parallel to 3x−2y=14 and passes through the point (-6, -11) in slope-intercept form.

Answer 1

3*-6-2*-11=14

-18+22=14

22=14+18

10

uwu

Answer 2

• y = 3/2x - 2

Explanation:

Given line

• 3x - 2y = 14

To find

• Parallel line passing through the point (-6, -11)

Solution

Let's put the given line into slope-intercept form

• 3x - 2y = 14
• 2y = 3x - 14
• y = 3/2x - 7

Parallel line has same slope, the equation of the parallel line is

• y = 3/2x + b

Finding y-intercept using the point (-6, -11)

• -11 = 3/2*(-6) + b
• -11= -9 + b
• b = -2

So the line is

• y = 3/2x - 2