Question

I don’t know how to do this, please help

Answer 1

`\huge\boxed{(1, -3)}`

Explanation:

In order to find the solution to this system of equations, our goal is to get one variable on one side of the equation.

With the equations d
`10x-2y=16`, and
`10x-2y=16`, we know that we can multiply
`10x-2y=16` by -1 and the x terms will cancel out (as 10 - 10 = 0).

`-1(10x-2y=16) = -10x + 6y = -16`

Now we add this equation to the first.

`10x+9y=-17`

`-10x+2y=-16`

_______________

`11y=-33`

Divide both sides by 11 and we get
`y=-3`.

Now that we know the value of y, we can substitute it inside an equation and find the value of x. Let's substitute it inside
`10x-2y=16`.

`10x-2(-3)=16\\10x+6=16\\10x=10\\\\x=1`

So x = 1.

Hope this helped!

Hope this helped!