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1. Factor x²+5x-24
2. Factor 2n²-5n-3

User Richard H
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1 Answer

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Given problems;

1. Factor; x²+5x-24

To factor this equation, we must understand that this is a quadratic equation.

A quadratic equation usually has two roots.

  • Equate to zero;

x²+5x-24 = 0

  • Then find two numbers whose product is -24 and their sum is +5

the numbers are +8 and -3

then replace 5x with the number;

x² + 8x - 3x - 24 = 0

Now factorize;

x(x +8) - 3(x + 8) = 0

(x-3)(x+8) = 0

Factoring gives (x-3)(x+8)

2. Factor 2n² - 5n -3;

Equate to zero;

2n² - 5n -3 = 0

Find the number whose sum is -5 and the product gives -6( 2 x -3);

the number is -6 and +1;

2n² - 6n + n -3 = 0

2n(n-3) + 1(n-3) = 0

(2n + 1)(n-3) = 0

The factor of the equation is (2n + 1)(n-3).

User Gleber
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