Answer:
Let the width of the rectangle be w.
Let the length of the rectangle be l.
★ If the length is 3 feet longer than the width, then the length can be written in terms of the width as:
Now, the formula for finding the perimeter is p = 2l + 2w.
Substituting the values in this formula -
![\\ \implies \sf \: p = 2(w + 3) + 2w \\ \\ \\ \implies \sf \: p = 2w + 6 + 2w \\ \\ \\ \implies \sf \: p = 4w + 6 \\](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6iwn5qj44phu2ks3i6slarj7f26ls1gz0r.png)
Substituting P = 30 for p ( allows us to solve for p) -
![\\ \implies \sf \: 30 = 4w + 6 \\ \\ \\ \implies \sf \: 30 - 6 = 4w + 6 - 6 \\ \\ \\ \implies \sf24 = 4w \\ \\ \\ \implies \sf \: w = (24)/(4) \\ \\ \\ \dag \: \large{ \underline{ \boxed{ \sf{ \: w = 6 \: cm}}}} \\](https://img.qammunity.org/2021/formulas/mathematics/middle-school/obgwu44pmt7v6jhbjjp87b93c464gaqpxd.png)
Substituting w = 6 for l in the equation l = w + 7 -
![\\ \implies \sf \: l = 6 + 7 \\ \\ \\ \implies \sf \blue{l = 13 \: cm}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/iwylm7ydw2vok63ekqdyi2a3nsqu9mzl8h.png)