Question

Solve by quadratic formula:
8a2 + 6a + 5=0

Answer 1

`x = (-3 \pm i√(31))/(8)`

Explanation:

Quadratic Formula:
`x = (-b \pm √(b^2-4ac) )/(2a)`

√-1 is imaginary number i

Step 1: Define Quadratic

8a² + 6a + 5 = 0

a = 8

b = 6

c = 5

Step 2: Plug into Quadratic Formula

`x = (-6 \pm √(6^2-4(8)(5)) )/(2(8))`

Step 3: Solve

`x = (-6 \pm √(36-160) )/(16)`

`x = (-6 \pm √(-124) )/(16)`

`x = (-6 \pm √(124) (√(-1) ))/(16)`

`x = (-6 \pm i√(124))/(16)`

`x = (-6 \pm 2i√(31))/(16)`

`x = (2(-3 \pm i√(31)))/(16)`

`x = (-3 \pm i√(31))/(8)`