Question

NHCI(s) = NH3(g) + HCl(g) at 427°C, Kp = 4.8. Calculate Kc​

Answer 1

`\tt Kp=Kc(RT)^(\Delta n)`

NH₄Cl (s) ⇔ NH₃ (g) + HCl (g)

Δn = 2 (gas only)

R = 0.082

T = 427 + 273 = 700 K

4.8 = Kc (0.082 x 700)²

Kc = 1.45 x 10⁻³