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What is the vertex of the parabola x^2+2x-8=y

User Jash Shah
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1 Answer

2 votes

Answer:

Vertex: (-1,-9)

Explanation:

The vertex of an up-down facing parabola of the form y=ax^2+bx+c is x=-b/2a

Plug the values into the equation

a=1, b=2, c=-8

x=-2/(2*1)

Simplify

x=-1

Plug in x=-1 to find the y value

y=1(-1)^2 + 2(-1) + (-8)

y= -9

Then put them in a coordinate pair

Vertex: (-1,-9)

User Pwightman
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