Question

The width of a rectangle is 8 inches longer than its length. The perimeter is 104 inches.

What is the
and
of the rectangle.

Answer 1

The width of the rectangle is 56 and the length is 48

Explanation:

divide the perimeter in half (52 + 52)

then subtract 4 from one of the 52's

you get the answer of 56 and 48

Your answer can be checked by conferming that 56 - 48 = 8 so the width of a rectangle is 8 inches longer than its length.

Answer 2

Width of one side is 30 inches, Length of one side is 22 Inches and Areas is 660 Inches Squared

Explanation:

W= 8 + L

P = ( W x 2 ) + ( L x 2 )

104 = 2( 8 + L ) + ( L x 2 )

104 = 16 + 2L + ( L x 2 )

104 = 16 + 2L + 2L

104 = 16 + 4L

-16 -16

88 = 4L

88 / 4 = 4L / 4

22 = L

W = 8 + 22

W = 30

Area = L x W

A = 22 * 30

A = 660