Question

A child rides a bicycle from rest, reaching a velocity of 3.8 m/s [E] after 4.7 s. What is the acceleration of the bicycle?

Answer 1

The acceleration of the bicycle is calculated using the equation of motion v_f = v_i + a * t. Given the final velocity of 3.8 m/s and a time of 4.7 seconds, the acceleration is found to be 0.8085 m/s^2 eastward.

Step-by-step explanation:

The student was asked to calculate the acceleration of a bicycle when a child rides it from rest to a velocity of 3.8 m/s eastward in 4.7 seconds. To find the acceleration, we can use the following equation of motion which relates initial velocity (vi), final velocity (vf), acceleration (a), and time (t):

vf = vi + a * t

Since the initial velocity is from rest (vi = 0), the equation simplifies to:

vf = a * t

To solve for acceleration, we can rearrange the equation as follows:

a = vf / t

Plugging in the known values:

a = 3.8 m/s / 4.7 s

a = 0.8085 m/s2

Therefore, the acceleration of the bicycle is 0.8085 m/s2, directed eastward.

Answer 2

0.81 m/s^2

Step-by-step explanation:

A child rides a bicycle from rest

The child reaches a velocity of 3.8m/s

The time is 4.7 secs

Therefore the acceleration can be calculated as follows

v= u + at

3.8= 0 + a(4.7)

3.8= 0 + 4.7a

3.8-0= 4.7a

3.8= 4.7a

a= 3.8/4.7

= 0.81 m/s^2

Hence the acceleration is 0.81 m/s^2