Question

A net force of 200 N is applied to a 20 kg cart that is already moving at 3

m/s. The final speed of the cart was 8 m/s. For how long was the force
applied? *

Answer 1

t=0.5 seconds

Step-by-step explanation:

Given that,

Force, F = 200 N

Mass of a cart, m = 20 kg

Initial speed of a cart, u = 3 m/s

Final speed, v = 8 m/s

Let t is the time for which the force is applied. Force applied to an object is given by :

F = ma

or

`F=(m(v-u))/(t)\\\\t=(m(v-u))/(F)\\\\t=(20* (8-3))/(200)\\\\t=0.5\ s`

So, for 0.5 seconds the force is applied.