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Write the equation of the link that passes through point A and the origin

Write the equation of the link that passes through point A and the origin-example-1
User Bricklore
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Answer: Choice B

y + 3 = (1/2)(x + 6)

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Step-by-step explanation:

Point A is located at (x1,y1) = (-6,-3)

The origin is located at (x2,y2) = (0,0)

Find the slope of the line through those two points

m = (y2-y1)/(x2-x1)

m = ( 0 - (-3) )/( 0 - (-6) )

m = ( 0 + 3 )/( 0 + 6 )

m = 3/6

m = 1/2

Now turn to point slope form

y - y1 = m(x - x1)

y - (-3) = (1/2)(x - (-6))

y + 3 = (1/2)(x + 6)

Note: We could easily swap (x1,y1) and (x2,y2) to get an equivalent equation.

User Poelie
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