Question

1
Consider the graph shown below.

Find the distance between (16, 0) and (0, 12).

Answer 1

20

Explanation:

The formula of a distance between two points

`A(x,\ y_1);\ B(x_2,\ y_2)\\\\AB=√((x_2-x_1)^2+(y_2-y_1)^2)`

Substitute (16, 0) and (0, 12):

`d=√((0-16)^2+(12-0)^2)=√((-16)^2+12^2)=√(256+144)=√(400)=20`

You can use the Pythagorean theorem.

Look at the picture.

`d^2=16^2+12^2\\\\d^2=256+144\\\\d^2=400\to d=√(400)\\\\d=20`