If y=(x^2-4)^5(3x+4)^4

Chiseled asked Jul 18, 2023

239,055 views

36 votes

Chiseled asked Jul 18, 2023

2.7k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

17 votes

Answer:

y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

Explanation:

y=(x^2-4)^5(3x+4)^4

y'=[(d)/(dx)(x^2-4)^5](3x+4)^4+(x^2-4)^5[(d)/(dx)(3x+4)^4]

y'=10x(x^2-4)^4(3x+4)^4+(x^2-4)^5(12(3x+4)^3)

y'=10x(x^2-4)^4(3x+4)^4+12(x^2-4)^5(3x+4)^3

y'=2(3x+4)^3(x^2-4)^4(21x^2+20x-24)

Tbthorpe answered Jul 25, 2023

2.3k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers