Answer:
hello attached is the detailed solution
Explanation:
Laplace transform of the functions and the sketches are attached below
A) f(t) = u(t) + 3u(t-1) - 2u(t-2) - 2u(t-3)
F(s) =
![(1 + 3e^(-s) -2e^(-2s)-2e^(-3s) )/(s)](https://img.qammunity.org/2021/formulas/mathematics/college/zr1apzu5mucq7rwkwgc5qnmhpldd9js0ym.png)
B) f(t) = 2u(t+2) - 3u(t+1) +4u(t-1) - 3u(t-2)
F(s) =
![(2e^(2s) - 3e^s + 4e^(-s) -3e^(2s) )/(s)](https://img.qammunity.org/2021/formulas/mathematics/college/9q8q4ecyt0fxizbg9fs03ti26vrht0hbix.png)
attached below is the remaining part of the answer