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Given: (−10,2) and (3,5), the midpoint is???

2 Answers

3 votes

Answer:


\huge{ \boxed{ \sf{( ( - 7)/(2) \:, \: (7)/(2))}}}

Explanation:


\star{ \sf{Let \: the \: points \: be \: A \: and \: B}}


\sf{A( - 10 ,\: 2) \longrightarrow{ \: (x1 \:, y1)}}


\sf{B(3 \:, 5) \: \longrightarrow} \: \sf{(x2 \:, y2)}


\underline{ \text{Finding \: the \: midpoint}} :


\boxed{ \sf{Midpoint \: = \: ( (x1 + x2)/(2) \: , (y1 + y2)/(2) )}}


\mapsto{ \sf{Midpoint = ( ( - 10 + 3)/(2) \: , (2 + 5)/(2) }})


\text{Remember!} :

  • The positive integers are always added and posses the positive ( + ) sign.
  • The negative integers are always added but posses the negative ( - ) sign.
  • The negative and positive integers are always subtracted but posses the sign of the bigger integer.


\mapsto{ \sf{Midpoint = ( ( - 7)/(2) , \: (7)/(2) }})

Hope I helped!

Best regards! :D

~
\text{TheAnimeGirl}

Given: (−10,2) and (3,5), the midpoint is???-example-1
User Ingwie Phoenix
by
8.3k points
3 votes

Answer:

M=(−7/2,7/2).

Explanation:

User CoolEsh
by
8.5k points

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