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The air in a tire pump has a volume of 1.50 L at a temperature of 5.00ºC. If the temperature is increased to 30.0 ºC and the pressure remains constant, what is the new volume? Do not forget to convert ºC to K.

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4 votes

Answer:

The new volume is 1.63 L

Explanation:

A tire pump has a volume of 1.5 L, while the temperature is 5 °C When the temperature changes to 30 °C, the volume will change as well.

The pressure remains constant.

Since the pressure is constant we can use the following formula:

V1/T1 = V2/T2

V1 = the initial volume = 1.5L

T1 = the initial temperature = 5 °C = 273.15 + 5 = 278.15 K

V2 = the final volume = TO BE DETERMINED

T2 = the final temperature = 30 °C = 273.15 + 30 = 303.15 K

1.5L/ 278.15 Kelvin = V2/303.15 K

V2 = (1.50L * 303.15 Kelvin) / 278.15 Kelvin = 1.63 L

When the temperature increased from 5°C to 30°C, the volume will change to 1.63 L

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