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F(x) = x3 – 13x2 + 52x – 60
Find the roots

User Puce
by
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1 Answer

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Answer:

The roots are 2, 5 and 6.

Explanation:

As the last term is 60 we could see if one root is 2:

2^3 - 13(2)^2 + 52*2 - 60

= 8 - 52 + 104 - 60

= 112 - 112 = 0

So x = 2 is one root and x - 2 is a factor.

Long multiplication:

x - 2 (x^3 - 13x^2 + 52x - 60 ( x^2 - 11x + 30 <--- Quotient

x^3 - 2x^2

- 11 x^2 + 52x

- 11x^2 + 22x

30x - 60

30x - 60

So x^2 - 11x + 30 = 0

(x - 6)(x - 5) = 0

x = 6, 5.

User JxDarkAngel
by
6.7k points
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