Question

Question 2 (1 point)

A tennis ball rolls off the edge of a table. the table is 0.55m tall and the tennis ball
lands 0.12m away from the table.
3
What is the initial vertical velocity?
0 m/s2
9
.12m
O m/s
-9.8m/s2
h
Question 3 (1 point)

Answer 1

The initial vertical velocity is zero, u = 0 m/s

Step-by-step explanation:

Given;

height of the table, h = 0.55 m

horizontal distance traveled by the tennis, x = 0.12 m

Apply the following kinematic equation;

h = ut + ¹/₂gt²

where;

u is the initial vertical velocity = 0, since the tennis ball rolled off the edge of a table.

h = ¹/₂gt²

The time to fall from the vertical height is given by;

`t = \sqrt{(2h)/(g) } \\\\t = \sqrt{(2(0.55))/(9.8) }\\\\t = 0.335 \ s`

The initial horizontal velocity of the tennis is given by;

x = vₓt

vₓ = x / t

vₓ = (0.12) / (0.335)

vₓ = 0.358 m/s

Therefore, the initial vertical velocity is zero, u = 0 m/s and initial horizontal velocity, vₓ is 0.358 m/s