Answer:
C
Explanation:
Remember that if s(t) is a position function then:
is the velocity function and
is the acceleration function.
So, to find the acceleration, we need to solve for the second derivative of our original function. Our original function is:

So, let's take the first derivative first with respect to t:
![(d)/(dt)[s(t)]=(d)/(dt)[t^2+4t+10]](https://img.qammunity.org/2021/formulas/mathematics/college/2bpjukm6hgaxfpwn3xowqfj2t7sz5myr4m.png)
Expand on the right:
![s'(t)=(d)/(dt)[t^2]+(d)/(dt)[4t]+(d)/(dt)[10]](https://img.qammunity.org/2021/formulas/mathematics/college/tbqge4gp3b0qlqgxntdim0lfc1nxq78xmh.png)
Use the power rule. Remember that the derivative of a constant is 0. So, our derivative is:

This is also our velocity function.
To find acceleration, we want to second derivative. So, let's take the derivative of both sides again:
![(d)/(dt)[s'(t)]=(d)/(dt)[2t+4]](https://img.qammunity.org/2021/formulas/mathematics/college/7v4j8058a2cphjkk8tqq4wr4dc1o6d5oc4.png)
Again, expand the right:
![s''(t)=(d)/(dt)[2t]+(d)/(dt)[4]](https://img.qammunity.org/2021/formulas/mathematics/college/aqbbgt54r1npp2y07xxqwhp6ormeaysqjn.png)
Power rule. This yields:

So, our answer is C.
And we're done!