Question

50 POINTS

19. Ift(x) = 7 - 2x and t(x) = 0, then find x.


20. If h(x) = 4x + 2, then h(x + 3) =

Answer 1

see below

Explanation:

(x) = 7 - 2x

Let t(x) =0

0 = 7-2x

Subtract 7 from each side

-7 = -2x

Divide by -2

-7/-2 =-2x/-2

7/2 =x

h(x) = 4x + 2

Replace x with x+3

h(x+3) = 4(x+3) + 2

Distribute

= 4x+12 +2

=4x+14

Answer 2

19)
`x=(7)/(2)`

20)
`h(x+3)=4x+14`

Explanation:

19)

We have the function:

`t(x)=7-2x`

And we want to find x such that t(x)=0.

So, substitute 0 for t(x):

`0=7-2x`

Solve for x. Subtract 7 from both sides:

`-7=-2x`

Divide both sides by -2:

`(7)/(2)=x`

Flip:

`x=(7)/(2)`

20)

We have:

`h(x)=4x+2`

To find h(x+3), substitute (x+3) for x. This yields:

`h(x+3)=4(x+3)+2`

Multiply:

`h(x+3)=4x+12+2`

Add:

`h(x+3)=4x+14`

And we're done!